Чтобы отсортировать словарь по его значениям

Библиотека Python разработчика | Книги по питону

Чтобы отсортировать словарь по его значениям, используйте функцию sorted с пользовательской функцией ключа:


>>> d = dict(a=1, c=3, b=2)
>>> sorted(d.items(), key=lambda item: item[1])
[('a', 1), ('b', 2), ('c', 3)]

Однако такая функция уже существует в модуле operator:


>>> from operator import itemgetter
>>> sorted(d.items(), key=itemgetter(1))
[('a', 1), ('b', 2), ('c', 3)]

Вы также можете сортировать только ключи вместо пар ключ-значение:


>>> sorted(d, key=lambda k: d[k])
['a', 'b', 'c']

И снова, эту лямбду можно заменить уже существующим методом:


>>> sorted(d, key=d.get)
['a', 'b', 'c']

👉@BookPython

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Create: 2025-04-27
Last Update: 2025-06-21 14:57:33

Чтобы отсортировать словарь по его значениям, используйте функцию sorted с пользовательской функцией ключа:


>>> d = dict(a=1, c=3, b=2)
>>> sorted(d.items(), key=lambda item: item[1])
[('a', 1), ('b', 2), ('c', 3)]

Однако такая функция уже существует в модуле operator:


>>> from operator import itemgetter
>>> sorted(d.items(), key=itemgetter(1))
[('a', 1), ('b', 2), ('c', 3)]

Вы также можете сортировать только ключи вместо пар ключ-значение:


>>> sorted(d, key=lambda k: d[k])
['a', 'b', 'c']

И снова, эту лямбду можно заменить уже существующим методом:


>>> sorted(d, key=d.get)
['a', 'b', 'c']

👉@BookPython

BY Библиотека Python разработчика | Книги по питону

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